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Assignment

Assignment: Matrix Algebra for Homogeneous & Non-Homogeneous Linear Algebraic System

Assignment Question

The following linear algebraic equations, [Q]{c}={b}[Q]\{c\}=\{b\} represents the 4 dof lake system, where RHS vector consists of the mass loading rate of chloride to each of the 4 lakes and c1c_1, c2c_2, c3c_3 and c4=c_4= the resulting chloride concentrations for Lakes Powell, Mead, Mohave, and Havasu, respectively.

Figure for Assignment
[q12000q12q23000q23q34000q34q44]{c1c2c3c4}={b1b2b3b4}={750.530010230}\begin{bmatrix} q_{12}&0&0&0\\ -q_{12}&q_{23}&0&0\\ 0&-q_{23}&q_{34}&0\\ 0&0&-q_{34}&q_{44} \end{bmatrix} \begin{Bmatrix} c_1\\c_2\\c_3\\c_4 \end{Bmatrix} = \begin{Bmatrix} b_1\\b_2\\b_3\\b_4 \end{Bmatrix} = \begin{Bmatrix} 750.5\\300\\102\\30 \end{Bmatrix}

a. If the volumetric flow rates are given as follow: q12=13.422q_{12} = 13.422, q23=12.252q_{23} = 12.252, q34=12.377q_{34} = 12.377 and q44=11.797q_{44} = 11.797. Use determinant analysis to check the condition of the system, then predict the characteristic of the solution without calculation.

(1 mark)

b. Solve the concentrations in each of the four lakes by using GEwPP method. The calculation must involve the scaling, partial pivoting, forward elimination and the backward substitution procedures.

(2 mark)

c. Discuss the advantage of GEwPP method and disadvantage of Cramer’s rule in terms of efficiency and accuracy for solving high dimension inverse problem with singular matrix.

(1 mark)

d. Obtain the eigenvalue matrix and normalized eigenvector matrix of the [Q][Q]. Note:Arrange the eigenvalue, λ\lambda in ascending order (λ1<λ2<<λn)(\lambda_1<\lambda_2<\ldots<\lambda_n).

(5 mark)

e. By using the result in (d), compute the matrix K\mathbf{K} indirectly by simplify the calculation using the following information: Q=K4\mathbf{Q}=\mathbf{K}^4, (QλI)c=0(\mathbf{Q}-\lambda\mathbf{I})\mathbf{c}=0, eigenvalue property of Qk=PDkP1\mathbf{Q}^\mathbf{k}=\mathbf{P}\mathbf{D}^\mathbf{k}\mathbf{P}^{-1}.

K=[q12000q12q23000q23q34000q34q44]4{c1c2c3c4}λ3\mathbf{K}= \begin{bmatrix} q_{12}&0&0&0\\ -q_{12}&q_{23}&0&0\\ 0&-q_{23}&q_{34}&0\\ 0&0&-q_{34}&q_{44} \end{bmatrix}^4 \begin{Bmatrix} c_1\\c_2\\c_3\\c_4 \end{Bmatrix}_{\lambda_3}

where {c}λ3=\{c\}_{\lambda_3} = normalized eigenvector of the 3rd eigenvalue (i.e 2nd largest)

(1 mark)

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